The work done by $200 c a l o r i e$ of heat in isothermal expansion of ideal gas is:

- 836.8 J

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- 418.4 J

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- 555.2 J

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664.5 J

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Solution

The correct option is A $- 836.8 J$
From first law of thermodynamics
$△ U = q + w$

Here, $△ U = 0$ , since process is isothermal.
$q = - w$
$w = - 200 c a l$

So work done will be $200 c a l o r i e$
Again,
$1 c a l = 4.184 J$
So work done = $- 200 \times 4.184 J = - 836.8 J$

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