wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The work done by a gas when it undergoes a state change from 1 2 isothermally is


A

nRTln(V1V2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

nRTln(V2V1)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

nRT(V1V2)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

nRT(V2V1)

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B

nRTln(V2V1)


For an isothermal process T is constant.

Therefore from ideal gas equation we get -
pV = nRT

p=nRTV ...(1)

We know that the work done in any process can be calculated using -

W=pdV ...(2)

From (1) and (2) -

W=v2v1nRTVdV

=nRTv2v1dVV
W=nRTln(V2V1).


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Thermodynamic Processes
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon