Question

The work done by electric field in carrying a point charge $5\mu \text{C}$ from a point $A$ to point $B$ is $10\text{mJ}$. The potential difference $V_B-V_A$ is:

• A. $+2\text{kV}$
• B. $-2\text{kV}$
• C. $+\frac{1}{2}\text{kV}$
• D. $-\frac{1}{2}\text{kV}$

Answer 1

The correct option is B $-2\text{kV}$

We know,
$\Delta V=V_B-V_A=-\frac{W_{\text{electric force}}}{q}$
$\Rightarrow V_B-V_A=-\frac{10\times {10}^{-3}}{5\times {10}^{-6}}=-2\times {10}^3\text{V}=-2\text{kV}$