Question

The work done by electric field in carrying a point charge of 5$\mu$C from a point A to point B is 10 mJ. The potential difference $V_A-V_B$ is the:

• A. +2 kV
• B. -2 kV
• C. +2000V
• D. -2000V

Answer 1

The correct option is C +2000V

$W=q\Delta V$

$W=q(V_A-V_B)=10mJ$ (Given)

$q(V_A-V_B)=10\times {10}^{-3}$

$V_A-V_B=\frac{{10}^{-2}}{5\times {10}^{-6}}=2000V$