The correct option is C 9PoVo
Work done : ∫v2v1Pdv
We can decompose the path ABCDEFGHA into AB−BC−CD−DE−EF−FG−GH−HA
WXY= work done from X to Y
Since from A to B, pressure is Po, WAB=Po(Vo−3Vo)=−2PoVo
Since there is no change in volume from B to C, WBC=0
WCD=(4Po)(3Vo)=12PoVo
WDE=0 in the same manner as WBC
WEF=−4PoVo
WFG=o
WGH=3PoVo
WHA=0
Adding all, WABCDEFGHA=9PoV0