The work done by gas in process ABCDEFGHA is $X P_{0} V_{0}$ then X is :

Open in App

Solution

Work done : $\int_{v_{1}}^{v_{2}} p d v$
We can decompose the path ABCDEFGHA into A->B->C->D->E->F->G->H->A
$W_{X Y} =$ work done from X to Y
Since from A->B, pressure is $P_{0}$ , $W_{A B} = P_{0} (V_{0} - 3 V_{0}) = - 2 P_{0} V_{0}$
Since there is no change in volume from B->C, $W_{B C} = 0$
$W_{C D} = (4 P_{0}) (3 V_{0}) = 12 P_{0} V_{0}$
$W_{D E} = 0$ in the same manner as $W_{B C}$
$W_{E F} = - 4 P_{0} V_{0}$
$W_{F G} = 0$
$W_{G H} = 3 P_{0} V_{0}$
$W_{H A} = 0$
Adding all, $W_{A B C D E F G H A} = 9 P_{0} V_{0}$

Suggest Corrections

Similar questions

A B

\to

Δ

Join BYJU'S Learning Program