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Question
The work done by the force 4i−3j+2k in moving a particle along a straight line from the point (3,2,−1) to (2,−1,4) is:
The work done by the force 4i−3j+2k in moving a particle along a straight line from the point (3,2,−1) to (2,−1,4) is:
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Solution
The correct option is C 15 units
Force, →F=4^i−3^j+2^kDisplacement vector is →s=(2−3)^i+(−1−2)^j+(4+1)^k=−^i−3^j+5^kHence, work done W=→F⋅→s=(4^i−3^j+2^k)⋅(−^i−3^j+5^k)=−4+9+10=15units
Force, →F=4^i−3^j+2^k
Displacement vector is →s=(2−3)^i+(−1−2)^j+(4+1)^k=−^i−3^j+5^k
Hence, work done
W=→F⋅→s=(4^i−3^j+2^k)⋅(−^i−3^j+5^k)=−4+9+10=15units
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