The work done by the frictional force on a surface in drawing a circle of radius r on the surface having coefficient of friction μk by a pencil of negligible mass with a normal pressing force N is :
A
0.0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
−2πr2μkN
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
−3πr2μkN
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
−2πrμkN
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D−2πrμkN The kinetic frictional force at any instantaneous position is f=μkN (Tangentially)
For elementary displacement dl, the work done by f is dW=→f.→dl dW=−fdl
−ve sign indicates that f,dl are in opposite direction. ∫dW=−∫fdl ∫W0dW=−μkN∫2πr0dl ⇒W=−2πrμkN