the work done by the machine (g= 10 m $s^{- 2}$

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Solution

Actual work done by the load
= load in Newtons × distance moved by load = 300 kgf × = (3= × 10) N × 15 m = 4500 J
Since efficiency of the machine = 75%
Work done by the machine45000J0.75 = 60000J

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the work done by the machine (g= 10 m s−2

Actual work done by the load= load in Newtons ×× distance moved by load = 300 kgf ×× = (3= ×× 10) N ×× 15 m = 4500 JSince efficiency of the machine = 75%Work done by the machine45000J0.7545000J0.75 = 60000J

the work done by the machine (g= 10 m $s^{- 2}$

Actual work done by the load
= load in Newtons × distance moved by load = 300 kgf × = (3= × 10) N × 15 m = 4500 J
Since efficiency of the machine = 75%
Work done by the machine45000J0.75 = 60000J