1
Question
The work done during combustion of 9×10−2Kg of ethane, C2H6 (g) at 300 K is:
(Given: R 8.314 J deg−1,mol−1, atomic mass C = 12, H = 1)
The work done during combustion of 9×10−2Kg of ethane, C2H6 (g) at 300 K is:
(Given: R 8.314 J deg−1,mol−1, atomic mass C = 12, H = 1)
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Solution
The correct option is D +18.71 kJ
2C2H6(g)+7O2(g)→4CO2(g)+6H2O(l)
C2H6(g)+3.5O2(g)→2CO2(g)+3H2O(l)
Δn=2−(1+3.5)=−2.5
Molar mass of ethane =2(12)+6(1)=30 g/mol
9×10−2kg ethane =9×10−2kg×1000g/kg=90g
90 g ethane =90g30g/mol=3mol ethane.
For 1 mole of ethane, Δn=−2.5
For 3 mole of ethane, Δn=−2.5×3=−7.5
Work done ,W=−ΔnRT
W=(−7.5)×8.314J/mol/K×300K
W=18707J
W=18.71kJ
2C2H6(g)+7O2(g)→4CO2(g)+6H2O(l)
C2H6(g)+3.5O2(g)→2CO2(g)+3H2O(l)
Δn=2−(1+3.5)=−2.5
Molar mass of ethane =2(12)+6(1)=30 g/mol
9×10−2kg ethane =9×10−2kg×1000g/kg=90g
90 g ethane =90g30g/mol=3mol ethane.
For 1 mole of ethane, Δn=−2.5
For 3 mole of ethane, Δn=−2.5×3=−7.5
Work done ,W=−ΔnRT
W=(−7.5)×8.314J/mol/K×300K
W=18707J
W=18.71kJ
For 1 mole of ethane, Δn=−2.5
For 3 mole of ethane, Δn=−2.5×3=−7.5
Work done ,W=−ΔnRT
W=(−7.5)×8.314J/mol/K×300K
W=18707J
W=18.71kJ
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