Question

The work done during the expansion of a gas from a volume of $4$ dm${}^3$ to $6$ dm${}^3$ against a constant external pressure of $3$ atm is:

• A. $608J$
• B. $+304J$
• C. $304J$
• D. $-608J$

Answer 1

The correct option is D $-608J$

Work done during expansion of a gas is:-

$W=-P△V$

$W=-P(V_{final}-V_{initial})$

$W=-3(6-4)$

$W=-6L-atm=-6\times 101.32=\approx -608J$ $(\because 1d{m}^3=1L)$