Question

The work done during the expansion of a gas from a volume of $4{\text{dm}}^3\text{to}6{\text{dm}}^3$ against a constant external pressure of $3\text{atm}$ is ($1\text{L atm}=101.32\text{J}$)

• A. $-600\text{J}$
• B. $-608\text{J}$
• C. $+304\text{J}$
• D. $-304\text{J}$

Answer 1

The correct option is B $-608\text{J}$

$\text{Work}=-P_{\text{ext}}\times \text{volume change}$
$=-3\times (6-4)\text{Latm}=6\times 101.32\text{J}$
$=-607.92J\approx -608J$