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First Law of Thermodynamics

The work done...

Question

The work done in an open vessel at 300 K, when 112 g iron reacts with dil HCl is :

A

1200 cal

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B

600 cal

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C

300 cal

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D

200 cal

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Solution

The correct option is A 1200 cal
$F e + 2 H C l \to F e C l_{2} + H_{2} 1 m o l 1 m o l \frac{112}{56} = 2 m o l 2 m o l N o w, V_{2} = V_{H_{2}} a n d V_{1} = 0$
(For solid + liquid state)
Work done $= p (v_{2} - v_{1}) = p (H_{2} - 0) = p V_{H_{2}} = n_{H_{2}} R T = 2 \times 2 \times 300 = 1200 c a l$

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First Law of Thermodynamics

Standard XII Chemistry

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