The work done in an open vessel at 300 K- when 112 g iron reacts with dil HCl is -A- 1200 calB- 600 calC- 200 calD- 300 cal

Name: JEE - Grade 11 - Chemistry - Hydrocarbons - Session 02 - W01
Uploaded: 2022-07-04T10:36:42+05:30
Description: The correct option is A 1200 calFe+ 2HCl → FeCl_2 + H_2 1 mol 1 mol 11256 = 2 mol 2 mol Now, V_2 = V_H_2 and ...

The correct option is A 1200 calFe+ 2HCl → FeCl_2 + H_2 1 mol 1 mol 11256 = 2 mol 2 mol Now, V_2 = V_H_2 and ...

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Standard XII

Chemistry

First Law of Thermodynamics

The work done...

Question

The work done in an open vessel at 300 K, when 112 g iron reacts with dil HCl is :

1200 cal

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600 cal

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300 cal

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200 cal

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Solution

The correct option is A 1200 cal
$F e + 2 H C l \to F e C l_{2} + H_{2} 1 m o l 1 m o l \frac{112}{56} = 2 m o l 2 m o l N o w, V_{2} = V_{H_{2}} a n d V_{1} = 0$
(For solid + liquid state)
Work done $= p (v_{2} - v_{1}) = p (H_{2} - 0) = p V_{H_{2}} = n_{H_{2}} R T = 2 \times 2 \times 300 = 1200 c a l$

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First Law of Thermodynamics

Standard XII Chemistry

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The work done in an open vessel at 300 K, when 112 g iron reacts with dil HCl is :

The correct option is A 1200 calFe+2HCl→FeCl2+H21 mol 1 mol11256=2 mol 2 molNow,V2=VH2and V1=0 (For solid + liquid state) Work done =p(v2−v1)=p(H2−0)=pVH2=nH2RT=2×2×300=1200 cal