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Question

The work done in an open vessel at 300 K, when 112 g iron reacts with dil HCl to give FeCl2, is:

A
1.2kacl
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B
0.6kacl
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C
0.3kacl
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D
0.2kacl
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Solution

The correct option is B 1.2kacl
Solution:-
Molar mass of Fe=56g
Given mass of Fe=112g
As we know that,
No. of moles=MassMolar mass
Therefore, number of moles of Fe used-
n=11256=2 moles
As we know that,
w=PΔV=nRT[PV=nRT]
Given T=300K
w=2×2×300=1200 cal=1.2kcal
Hence the work done will be 1.2 kcal.

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