Question

The work done in an open vessel at $300K$, when $56g$ iron reacts with dilute $HCl$ is :

• A. $600cal$
• B. $300cal$
• C. $150cal$
• D. $100cal$

Answer 1

The correct option is A $600cal$

Here number of moles of $Fe=n=\frac{weight}{molecularwt.}=\frac{56}{56}=1$

Here, $R=2cal$

$W=\Delta n_{g}RT$ or $W=1\times 2\times 300K$

So, $W=600cal$

Therefore, option A is correct.