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Question

The work done in blowing a soap bubble of 10 cm radius is -
(surface tension of soap =0.03 N/m).

A
6.54×103 J
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B
7.54×103 J
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C
9.54×103 J
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D
8.54×103 J
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Solution

The correct option is B 7.54×103 J
Given,
Radius of soap bubble, R=10 cm=0.1 m
Surface Tension, T=0.03 N/m
We know, number of free surfaces for soap bubble, n=2
Work done = surface tension × change in surface area × number of free surfaces
W=T×ΔA×n
=0.03×4π(0.1202)×2
[ surface area =4πr2 ]
=7.54×103 J

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