Question

The work done in bringing a $20$ coulomb charge from point A to point B for distance $0.2m$ is $2joule$. The potential difference between the two points will be (volt )

• A. $2$
• B. $8$
• C. $0.1$
• D. $0.4$

Answer 1

The correct option is (C) $2$

Step 1, Given data

Charge = 20 C

Work done = 2 Joule

Step 2, Finding the potential difference

We know,

$V=\frac{Work\left(W\right)}{Charge\left(Q\right)}$

Putting all the values

$V=\frac{2J}{20C}$

After solving

V = 0.1 V

Hence the potential difference is 0.1 V