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Question
The work done (in joules) by a force →F=(−6x3^i) N in displacing a particle from x=4 m to x=−2 m is
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Solution
Given →F=6x3^i
For displacement along X axis,
work done by the force is
W=∫→F.−→dx=∫−6x3dx
As the particle moves from x=4 m to x=−2 m
W=−6∫−24x3 dx=−64[16−256]
W=32×240=360 J
For displacement along X axis,
work done by the force is
W=∫→F.−→dx=∫−6x3dx
As the particle moves from x=4 m to x=−2 m
W=−6∫−24x3 dx=−64[16−256]
W=32×240=360 J
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