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Byju's Answer
Standard VIII
Chemistry
Work
The work done...
Question
The work done in lifting a mass of 1 kg to a
height of 9.8 m is equal to :
A
1 J
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B
(
9.8
)
2
J
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C
9.8 J
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D
none of these
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Solution
The correct option is
B
(
9.8
)
2
J
Work = Force
∗
displacement
and Force = Mass
∗
acceleration
Acceleration = gravity and displacement = height
Force = mg, Work = mgh i.e 1
∗
9.8
∗
9.8 = (9.8)
2
J
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