Question

The work done in moving a unit positive charge from one end of a conductor to its other end is $10J$. Voltage across the ends of the conductor is .

• A. $10V$
• B. $1V$
• C. $20V$

Answer 1

The correct option is A $10V$

Let the voltage be $V$
Given, work done, $W=10J$ and charge, $Q=1C$.
We know, $V=\frac{W}{Q}=\frac{10}{1}=10V$.