The work done in placing a charge of 8- 10-18 C on a condenser of capacity 100- F is -

Two equal and opposite charges of $4 \times 10^{- 8} C$ when placed $2 \times 10^{- 2} c m$ away, form a dipole. If this dipole is placed in an external electric field of $4 \times 10^{8}$ newton/coulomb, the value of maximum torque and the work done in rotating it through $180^{o}$ will be

A condenser of capacity 16 mF charged to a potential of 20 V is connected to a condenser of capacity C charged to a potential of 10 V as shown in the figure. If the common potential is 14 V, the capacity C is equal to

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The work done in placing a charge of 8×10−18C on a condenser of capacity 100μF is :

The correct option is A 32×10−32J The work done in placing a charge Q on a condenser of capacity C is given by W=Q22CJ Here Q=8×10−18C and C=100×10−6F Therefore, Work done, W=(8×10−18)2200×10−6=32×10−32J

The work done in placing a charge of $8 \times 10^{- 18} C$ on a condenser of capacity $100 μ F$ is :