The work done in rotating a magnet of magnetic moment2A−m2in a magnetic field of 5×10−3T from the direction along the magnetic field to opposite direction to the magnetic field, is
A
Zero
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B
2×10−2J
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C
10−2J
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D
10J
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Solution
The correct option is B2×10−2J W=MB(1−cosθ); where θ=180∘ ⇒W=2MB⇒W=2×2×5×10−3=2×10−2J