Question

The work done in stretching a spring of spring constant $3000newton/m$ by $0.02m$ is :-

• A. $30J$
• B. $300J$
• C. $0.06J$
• D. $6J$

Answer 1

The correct option is C $0.06J$

Given that,

Spring constant , $k=300N/m$

Stretching in spring , $x=0.02m$

$\therefore \text{Work done in stretching}=\frac{1}{2}k{x}^2=\frac{1}{2}\times 300\times (2\times {10}^{-2}{)}^2=150\times 4\times {10}^{-4}=\frac{600}{10000}=0.06J$