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Byju's Answer
Standard XII
Physics
Work Done
The work done...
Question
The work done in the given figure is
A
3
×
10
5
J
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B
2
×
10
5
J
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C
10
5
J
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D
zero
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Solution
The correct option is
C
10
5
J
The work done is the area under the PV graph. Thus we get the area as
10
5
×
(
2
−
1
)
m
3
=
10
5
J
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0
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