Question

The work done to move $25\times {10}^{18}$ electrons between two points is 100 mJ. What is the potential difference between the two points?

Answer 1

Work done, $W=q|\Delta V|\to$ (1)

$q=25\times {10}^{18}\times 1.6\times {10}^{-19}C$

$W=100\times {10}^{-3}J$

$\left(1\right)\Rightarrow 100\times {10}^{-3}=25\times {10}^{18}\times 1.6\times {10}^{-19}|\Delta V|$

$\Rightarrow \Delta V=\frac{100\times {10}^{-3}}{25\times 1.6\times {10}^{-1}}=2.5\times {10}^{-2}V$