Question

The work done when $6.5$ g of zinc reacts with dil. HCl is an open beaker at $298$ K is:

• A. -3.26 J
• B. -2.446 J
• C. 4.56 J
• D. none of these

Answer 1

The correct option is B -2.446 J

Let us consider the equation

number of moles$=\frac{6.5}{65}=0.1$ mol

$W=-P\times V=-1\times V=-V$

Implies that

$=\frac{-nRT}{9}=\frac{-0.1\times 0.0821\times 298}{1}=-2.44658$

The correct answer is B.