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Question

The work function of a metal is 1eV. On making light of wavelength 3000˚A incident on this metal, the velocity of photoelectrons emitted from it for photoelectric emission will be

A
2955km/s
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B
4200km/s
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C
1100km/s
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D
3000km/s
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Solution

The correct option is C 1100km/s
The given answers are having the dimension of length [L]. It can be solvable.
The photo electric effect can be written as:

E=mv22+ϕ

mv22=Eϕ=ΔE

So, v=[2E/m)]
Now, the work function of a metal is 1eV=1.6×1019

And energy of the photon is hcλ=6.6×1019

So, ΔE=5.6×1019
Now the velocity of the photo electron is v=[2E/m)]=1109053m/s=1100km/s
So, the answer is option (C).

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