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Question

# The work function of a metal is 1eV. On making light of wavelength 3000ËšA incident on this metal, the velocity of photoelectrons emitted from it for photoelectric emission will be

A
2955km/s
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B
4200km/s
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C
1100km/s
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D
3000km/s
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Solution

## The correct option is C 1100km/sThe given answers are having the dimension of length [L]. It can be solvable. The photo electric effect can be written as:E=mv22+ϕmv22=E−ϕ=ΔESo, v=√[2∗E/m)]Now, the work function of a metal is 1eV=1.6×10−19And energy of the photon is hcλ=6.6×10−19So, ΔE=5.6×10−19Now the velocity of the photo electron is v=√[2∗E/m)]=1109053m/s=1100km/sSo, the answer is option (C).

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