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Question

The work function of a metallic surface is 5.01 eV. The photo-electrons are emitted when light of wavelength 2000A falls on it. The potential difference applied to stop the fastest photo-electrons is
[h=4.14×1015 eV sec]

A
1.2 volts
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B
2.24 volts
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C
3.6 volts
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D
4.8 volts
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Solution

The correct option is A 1.2 volts
Energy of incident light E=123752000=6.18 eV
According to relation E=W0+eV0
V0=(EW0)e=(6.18 eV5.01 eV)e=1.17 V1.2 V

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