The work function of metals is in the range of $2$ eV to $5$ eV. Find which of the following wavelength of light cannot be used for photoelectric effect. (Consider, Planck constant $= 4 \times 10^{- 15}$ eVs, velocity of light $= 3 \times 10^{8} m / s$ ).

510 n m

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650 n m

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400 n m

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570 n m

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Solution

The correct option is B $650 n m$
The minimum wavelength to cause photoelectric effect $= \frac{h c}{E_{m a x}}$
$= \frac{4 \times 10^{- 15} \times 3 \times 10^{8}}{5} m$
$= 240 n m$
The maximum wavelength to cause photoelectric effect $= \frac{h c}{E_{m i n}}$
$= \frac{4 \times 10^{- 15} \times 3 \times 10^{8}}{2} m$
$= 600 n m$
Hence light of wavelength $650 n m$ is not acceptable.

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The work function of metals is in the range of 2 eV to 5 eV. Find which of the following wavelength of light cannot be used for photoelectric effect. (Consider, Planck constant =4×10−15eVs, velocity of light =3×108m/s).

The correct option is B 650nmThe minimum wavelength to cause photoelectric effect =hcEmax=4×10−15×3×1085m=240nmThe maximum wavelength to cause photoelectric effect =hcEmin=4×10−15×3×1082m=600nmHence light of wavelength 650nm is not acceptable.

The work function of metals is in the range of $2$ eV to $5$ eV. Find which of the following wavelength of light cannot be used for photoelectric effect. (Consider, Planck constant $= 4 \times 10^{- 15}$ eVs, velocity of light $= 3 \times 10^{8} m / s$ ).