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Question

The work functions for metals A, B and C are 1.92 eV,2.0 eV and 5.0 eV respectively. According to Einstein’s equation, the metals which will emit photoelectrons for a radiation of wavelength 4100 A is/are

A
None
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B
A only
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C
A and B only
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D
All the three metals
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Solution

The correct option is C A and B only
Einstein's equation is
E=ϕ+K.E
where E is the energy of incident radiation, ϕ is work function of metal and K.E is the kinetic energy of emitted electrons.

Thus for emission of photoelectrons, Eϕ
In this case, energy of incident radiation
E=hcλ=12431λ(in A) eV
=124314100=3.03 eV

E>ϕA and ϕB but E<ϕC
So, electrons will be emitted from both A and B.

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