The work of 146kJ is performed in order to compress 1 kilo mole of a gas adiabatically and in the process the temperature of the gas increases by 7∘C. The gas is:
(R=8.3Jmol−1K−1)
A
Diatomic
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B
A mixture of monoatomic and diatomic
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C
Monoatomic
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D
Triatomic
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Solution
The correct option is B Diatomic For adiabatic compression, ΔQ=0
Using first law of thermodynamics,
ΔU=−W
nCvΔT=−W
nf2RΔT=−W
f=−2WnRΔT
=−2×−1461×8.3×7
f≈5.02
Degrees of freedom is 2 for a diatomic gas. Hence, the gas is diatomic.