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Question

The work of 146 KJ is performed in order to compress on kilo mole of a gas adiabatically and in this process the temperature of the gas increases by 70C. The gas is (R=8.3Jmol1K1)

A
diatomic
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B
triatomic
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C
a mixture of monoatomic and diatomic
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D
monoatomic
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Solution

The correct option is A diatomic
Given : Increase in temperature, ΔT=T2T1=7oC
Work done on the system, W=146kJ=146×1000J
Number of moles of gas, n=1000

Work done in adiabatic process, W=nR(T2T1)γ1
146000=1000×8.3×7γ1
γ1=0.39
γ1.4
The gas is diatomic in nature.

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