wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

The work of 146 KJ is performed in order to compress on kilo mole of a gas adiabatically and in this process the temperature of the gas increases by 70C. The gas is (R=8.3Jmol1K1)

A
diatomic
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
triatomic
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
a mixture of monoatomic and diatomic
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
monoatomic
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A diatomic
Given : Increase in temperature, ΔT=T2T1=7oC
Work done on the system, W=146kJ=146×1000J
Number of moles of gas, n=1000

Work done in adiabatic process, W=nR(T2T1)γ1
146000=1000×8.3×7γ1
γ1=0.39
γ1.4
The gas is diatomic in nature.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Heat Capacity
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon