Question

The work of expansion in adiabatic process $\left(w_{adi}\right)$ is related to work of expansion in isothermal process $\left(w_{iso}\right)$ as:

• A. $w_{adi}=w_{iso}$
• B. $w_{adi}>w_{iso}$
• C. $w_{adi}=2w_{iso}$
• D. $w_{adi}<w_{iso}$

Answer 1

Answer: (D)

$w_{adi}<w_{iso}$

Work done =$-\int PdV$

From the above diagram, we can conclude that $w_{adia}$ is $<w_{iso}$

Hence, option D is correct.