The $x$ and $y$ coordinates of the particle at any time are $x = 5 t - 2 t^{2}$ and $y = 10 t$ respectively, where $x$ and $y$ are in meters and $t$ in seconds. The acceleration of the particle at $t = 2 s$ is

Q. The

x

and

y

co-ordinates of a particle at any time are

x = 5 t^{2} - 3 t + 6

and

y = 10 t^{2} + 2 t + 3

respectively, where

x

and

y

are in meters and

t

in seconds. Find the acceleration of the particle at

t = 1 s

Q. The x and y coordinates of a particle at any time

t

are given by

x = 2 t + 4 t^{2}

and

y = 5 t

, where x and y are in meter and

t

in second. The acceleration of the particle at

t = 5 s

is:

Q. A particle moves such that its x and y coordinates as a function of time are x = 2+

5 t^{2}

and y =

t^{3}

. Acceleration of particle at t = 2 sec is

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The x and y coordinates of the particle at any time are x=5t−2t2 and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2 s is

The correct option is B −4 m/s2AS Given, x=5t−2t2 y=10t So, dxdt=5−4t and d2xdt2=−4⇒ax Similarly, ay=d2ydt2=0 At t=2 s, →a=→ax^i+→ay^J ax=−4 m/s2 and ay=0 m/s2 →a=−4 m/s2

The $x$ and $y$ coordinates of the particle at any time are $x = 5 t - 2 t^{2}$ and $y = 10 t$ respectively, where $x$ and $y$ are in meters and $t$ in seconds. The acceleration of the particle at $t = 2 s$ is