The x and y coordinates of the particle at any time are x=5t−2t2 and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2s is
A
5m/s2
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B
−4m/s2
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C
−8m/s2
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D
0m/s2
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Solution
The correct option is B−4m/s2 AS Given, x=5t−2t2 y=10t
So, dxdt=5−4t and d2xdt2=−4⇒ax
Similarly, ay=d2ydt2=0
At t=2s, →a=→ax^i+→ay^J ax=−4m/s2anday=0m/s2 →a=−4m/s2