The X and Y form the above equation respectively are-CH 3 COOC 2 H 5 NaOH - X - YA- Ethanol and Acetic acidB- Ethanol and Methanoic acidC- Ethanol and MethanolD- Methanol and Acetic acid

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Byju's Answer

Standard X

Chemistry

Saponification

The X and Y f...

Question

The X and Y form the above equation respectively are:

$C H_{3} C O O C_{2} H_{5}$ $N a O H - --- \to$ X + Y

Ethanol and Acetic acid

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Methanol and Acetic acid

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Ethanol and Methanoic acid

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Ethanol and Methanol

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Solution

The correct option is A
Ethanol and Acetic acid

X and Y respectively are ethanol and acetic acid. This reaction is also called Saponification reaction.

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Similar questions

Q. The X and Y in the given equation respectively are:

C H_{3} C O O C_{2} H_{5} N a O H - --- \to X + Y

Q. How does ethanol reacts with
(a) metallic sodium
(b) acetic acid
(c) conc. H₂SO₄

Name :
(a) compound formed when acetic acid and ethanol react together.
(b) the reducing agent used to convert acetic acid into ethanol.
(c) the substance used to change acetic acid to acetic anhydride.

Q. The compound formed when ethanol is treated with acidified potassium dichromate

(K_{2} C r_{2} O_{7}

) is.

A solution is 25% H2O, 25% ethanol and 50% acetic acid by mass .Calculate the mole fraction of ethanol and acetic acid in the solution

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The X and Y form the above equation respectively are: CH3COOC2H5 NaOH−−−−→X + Y

The correct option is A Ethanol and Acetic acid X and Y respectively are ethanol and acetic acid. This reaction is also called Saponification reaction.

The X and Y form the above equation respectively are:

$C H_{3} C O O C_{2} H_{5}$ $N a O H - --- \to$ X + Y

The correct option is A
Ethanol and Acetic acid

X and Y respectively are ethanol and acetic acid. This reaction is also called Saponification reaction.