Given−the equation of a line is y=2x−3.To find out−the equation of the line in intercept form which is xa+yb=1 when a=x−intercept and b=y−intercept.Solution−y=2x−3⟹2x−y=3.Dividing both sides by 3 we get2x3−y3=1⟹x32+y−3=1.∴ x−intercept=a=32 and y−intercept=b=−3.Ans− Option B.