Question

The $x$ and $y$ intercepts of the following line is:

$y-3x=0$

• A. $a=0,b=3$
• B. $a=0,b=0$
• C. $a=0,b=-3$
• D. $a=0,b=\frac{1}{3}$

Answer 1

Answer: (B)

$a=0,b=0$

Given: The equation of a line is $y-3x=0$

To find out- the equation of the line in intercept form which is

$\frac{x}{a}+\frac{y}{b}=1$, when $a=x$-intercept and $b=y$-intercept.

Solution-

$y-3x=0$

$\Rightarrow y=3x+0$

Comparing this equation with slope-intercept form $y=mx+c$, we get

$c=0$

$\therefore y$-intercept is $0$.

Substituting $y=0$ in the given equation, we get

$3x=0$ or $x=0$

$\therefore x$-intercept is $0$.

$\therefore x$-intercept $=a=0$ $y$-intercept $=b=0$