The x coordinate of a particle moving along x axis is given in terms of time as x = (2-t) (t-6) metre. Find the displacement of the particle (in metre) from time t = 1 to t = 4 second.
9
Substituting the value, t=1 second in the equation, x = (2-t) (t-6) metre, we get, x= - 5 m
Substituting the value, t=4 second in the equation, x = (2-t) (t-6) metre, we get, x= 4 m
Displacement = final position - initial position =4 - ( - 5) = 9 m