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Snell's Law and Refractive Index

The x-y plane...

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The x-y plane is the boundary between two media . Medium-1 with z>0 has refractive index 2 and medium-2 with z<0 has refractive index 3 . A ray of light in medium -1 given by the vector A=63i + 83j-10k is incident on the plane of separation. Than find the unit vector along refracted ray ?

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x - y

plane is the boundary between two transparent media. Medium-1 with

z > 0

has refractive index

\sqrt{2}

- 2

z < 0

has a refractive index

\sqrt{3}

. A ray of light in medium-1 given by the vector

\to A = 6 \sqrt{3}^i + 8 \sqrt{3}^j - 10^k

is incident on the plane of separation. Find the unit vector in the direction of refracted ray in medium-2.

x - y

plane be the boundary between two transparent media. Medium 1 in

z \geq 0

has a refractive index of

\sqrt{2}

and medium 2 with

z < 0

has a refractive index of

\sqrt{3}

. A ray of light in medium 1 given by the vector

\to A = 6 \sqrt{3}^i + 8 \sqrt{3}^j + 10^k

is incident on the plane of separation. The angle of refraction in medium 2 is

Q. Let the x-z plane be the boundary between two transparent media. Medium

1

z \geq 0

has a refractive index of

\sqrt{2}

2

z < 0

has refractive index of

\sqrt{3}

. A ray of light in medium

1

given by the vector

\to A = 6 \sqrt{3}^i + 8 \sqrt{3}^j - 10^k

is incident on the plane of separation. The angle of refraction in medium

2

x - y

plane is the boundary between two transparent media. Medium 1 with

z \geq 0

has a refractive index

\sqrt{2}

and medium 2 with

z \leq 0

has a refractive index

\sqrt{3}

. A ray of light in medium 1 given by the vector

\to A = 6 \sqrt{3}^i + 8 \sqrt{3}^j - 10^k

is incident on the plane of separation. The angle between vector

\to A

and the positive

z

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