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Byju's Answer
Standard XII
Mathematics
Permutation under Restriction
The year next...
Question
The year next to
1988
having the same calendar as that of
1988
is
A
2016
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B
2004
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C
2010
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D
1999
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Solution
The correct option is
D
2016
Starting with 1988, we go on counting the number of odd days till the sum is divisible by 7.
Total number of odd days till
1999 are 14 but 1999 is not a leap year so it won't follow the same calendar as 1988
2004 are 20 which is not divisible by 7
2010 are 28 but 2010 is not a leap year so it won't follow the same calendar as 1988
2016 are 35 which is divisible by 7
Therefore, Calendar for 2016 the same as that of 1988.
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