The yellow colour solution of $N a_{2} C r O_{4}$ changes to orange red on passing $C O_{2}$ gas due to the formation of:

C r O_{5}

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C r O_{3}

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C r_{2} O_{7}^{2 -}

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C r_{2} O_{3}

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Solution

The correct option is B $C r_{2} O_{7}^{2 -}$
The yellow coloured solution of $N a_{2} C r O_{4}$ changes to orange red on passing $C O_{2}$ due to the formation of dichromte ion, $C r_{2} O_{7}^{2 -}$ .
The reaction is as follows:
$C O_{2} + H_{2} O \to H_{2} C O_{3} ⇌ 2 H^{+} + C O_{3}^{2 -}$
$2 C r O_{4}^{2 -} + 2 H^{+} ⇌ C r_{2} O_{7}^{2 -} (orange red) + H_{2} O$

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