The yield of product in the reaction $2 A (g) + B (g) ⇌ 2 C (g) + Q k J$ would be lower at

low temperature and low pressure

No worries! We‘ve got your back. Try BYJU‘S free classes today!

high temperature and high pressure

No worries! We‘ve got your back. Try BYJU‘S free classes today!

low temperature and to high pressure

No worries! We‘ve got your back. Try BYJU‘S free classes today!

high temperature and low pressure

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D high temperature and low pressure
The forward reaction is an exothermic reaction. Whereas the reverse reaction is an endothermic reaction. At high temperature, reverse reaction is favored so that more heat is absorbed which will nullify the effect of increased temperature.
Due to this the yield of $C$ will be lower. The number of moles for the reverse reaction increases from 2 to 3. At low pressure, reverse reaction is favored so that the number of moles increases which will nullify the effect of reduced pressure.
Due to this the yield of $C$ will be lower.

Suggest Corrections

Similar questions

In the reaction A(g) + 2B(g) $⇌$ C(g) + Q kJ of heat, more product will be obtained

or the forward reaction is favoured by

A_{2} (g) + 2 B (g) ⇌ C (g) + Q k J

2 S O_{2} (g) + O_{2} (g) ⇌ 2 S O_{3} (g) + X cal

S O_{3}

2 S O_{2} + O_{2} \to 2 S O_{3} Δ H = - Q c a l

S O_{3}

In the following reversible reaction $2 S O_{2} + O_{2} ⇌ 2 S O_{3} + Q C a l$

Most suitable condition for the higher production of $S O_{3}$ is

Join BYJU'S Learning Program