The Young's modulus of a rubber string 8 cm long and density 1.5 $\frac{k g}{m^{3}}$ is 5 $\times 10^{8} \frac{N}{m^{2}}$ . It is suspended from the ceiling in a room. The increase in length due to its own weight will be

9.6 X 10^-5 m

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9.6 X 10^-11 m

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9.6 X 10^-3 m

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9.6 m

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Solution

The correct option is B 9.6 X 10^-11 m
b):l = $\frac{L^{2} d g}{2 Y}$ = $\frac{(8 \times 10^{- 2})^{2} \times 1.5 \times 9.8}{2 \times 5 \times 10^{8}}$ = 9.6 $\times 10^{- 11} m$

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The Young's modulus of a rubber string 8 cm long and density 1.5 kgm3 is 5 ×108Nm2. It is suspended from the ceiling in a room. The increase in length due to its own weight will be

The correct option is B 9.6 X 10-11 mb):l = L2dg2Y = (8×10−2)2×1.5×9.82×5×108 = 9.6×10−11m

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The correct option is B 9.6 X 10^-11 m
b):l = $\frac{L^{2} d g}{2 Y}$ = $\frac{(8 \times 10^{- 2})^{2} \times 1.5 \times 9.8}{2 \times 5 \times 10^{8}}$ = 9.6 $\times 10^{- 11} m$