The Young's modulus of a rubber string 8 cm long and density 1.5 kgm3 is 5 ×108Nm2. It is suspended from the ceiling in a room. The increase in length due to its own weight will be
A
9.6×10−5m
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B
9.6×10−11m
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C
9.6×10−3m
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D
9.6 m
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Solution
The correct option is B9.6×10−11m b):l = L2dg2Y = (8×10−2)2×1.5×9.82×5×108 = 9.6×10−11m