wiz-icon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

The Young’s modulus of brass and steel are 10×1010N m2 and 2× 1011 N m2 respectively. A brass wire and a steel wire of the same length are extended by 1 mm under the same force. The radii of the brass and steel wires are RB and Rs respectively. Then

A
RA=2RB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
RS=RB2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
RS=4RB
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
RS=RB4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B RS=RB2

Y=Fπ R2×1 l
F, l and l are constants
Therefore R2 1Y

R2SR2B=YBYS=10112×1011= 12

or RSRB=12or Rs=RB2


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hooke's Law
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon