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Standard X

Physics

Nuclear Fusion

The Zeff va...

Question

The $Z_{e f f}$ value for the highest energy electrons in potassium ( $E = 418.8 K J / m o l$ ) is:

1.13

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2.46

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2.26

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2.5

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Solution

The correct option is C $2.26$
For potassium, highest energy electron lies in $n = 4$ .
$E = - \frac{Z_{e f f}^{2}}{n^{2}} \times 1310$ $k J / m o l$
$E = - 418.8 k J / m o l$
$Z_{e f f}^{2} = - \frac{(- 418.8) \times (16)}{1310}$
$Z_{e f f}^{2} = 5.11$
$Z_{e f f} = 2.26$

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The Zeff value for the highest energy electrons in potassium (E=418.8KJ/mol) is:

The correct option is C 2.26For potassium, highest energy electron lies in n=4.E=−Z2effn2×1310 kJ/molE=−418.8 kJ/molZ2eff=−(−418.8)×(16)1310Z2eff=5.11Zeff=2.26

The $Z_{e f f}$ value for the highest energy electrons in potassium ( $E = 418.8 K J / m o l$ ) is:

The correct option is C $2.26$
For potassium, highest energy electron lies in $n = 4$ .
$E = - \frac{Z_{e f f}^{2}}{n^{2}} \times 1310$ $k J / m o l$
$E = - 418.8 k J / m o l$
$Z_{e f f}^{2} = - \frac{(- 418.8) \times (16)}{1310}$
$Z_{e f f}^{2} = 5.11$
$Z_{e f f} = 2.26$