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Standard IX
Physics
Vernier Caliper
The zero erro...
Question
The zero error of a vernier is +1. Its zero correction is (take L.C
=
0.01 cm)
A
0.2 cm
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B
-0.2 cm
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C
-0.02 cm
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D
+0.02 cm
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Solution
The correct option is
C
-0.02 cm
Correction
=
−
[
L
.
C
×
2
]
c
m
=
−
[
0.01
×
2
]
c
m
=
−
0.02
c
m
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The main scale reading of a vernier calliper is obtained as 3.2 cm for an object placed in it. If the 4th division of the vernier scale coincides with a division on the main scale, and the magnitude of the positive zero error is 0.03 cm, what is the true length of the object in cm? Take L.C. = 0.01 cm.
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