The correct option is A -2 & -3
Given, x2+5x+6
Lets factorise before squaring.
x2+5x+6 =x2+3x+2x+6x(x+3)+2(x+3)(x+2)(x+3)
Squaring: x2+5x+6
(x2+5x+6)2=[(x+2)(x+3)]2=(x+2)2(x+3)2
Lets find zeroes,
(x+2)2=0; (x+3)2=0
Take square root on both side.
x+2=0; x+3=0x=−2; −3
Zeroes are -2 and -3.
Conclusion: Roots of the equation will be same.
x2+5x+6=(x+2)(x+3)
Zeroes are x=−2; −3