Question

The zeroes of the following quadratic polynomial $6x^2+x-5$ are .

• A. $\frac{1}{2}$ & 1
• B. $\frac{5}{6}$ & -1
• C. -1 & 2

Answer 1

The correct option is B $\frac{5}{6}$ & -1

$6x^2+x-5=0$
We need to find two numbers 'a' and 'b' such that
$a\pm b=1,a\times b=-30$
$\Rightarrow 6-5=1,-5\times 6=-306x^2+6x-5x-5=06x(x+1)-5(x+1)=0(6x-5)(x+1)=0$
So,
$6x-5=0$
$\Rightarrow x=\frac{5}{6}$
or,
$x+1=0$
$\Rightarrow x=-1$
Thus, the zeroes of the polynomial
$6x^2+x-5$ are $\frac{5}{6}$ and -1.